JB/T 8125-1999 Technical requirements for shell and tube oil coolers for internal combustion engines
Some standard content:
TCS27.920
Machinery Industry Standard of the People's Republic of China
JB/T 8125—1999
Internal combustion ezgiues--Tube and shell oil coolersSpecifications
Published on September 17, 1999
National Bureau of Machinery Industry
Implementation on January 1, 2000
JB/TB125—1999
2 Standard is a revision of the old J8125-95 (original 0B10906—89) "Technical conditions for shell and shell oil coolers for internal combustion engines". The source standard is modified, and the main technical content remains unchanged. The implementation of this standard replaces JB/T8125-95. The appendix A and appendix B of this standard are standard appendices. This standard was proposed and managed by the National Technical Committee for Standardization of Internal Combustion Engines. The originating unit of this standard is Shanghai Internal Combustion Engine Research Institute. The main drafter of the technical standard is Chen Daneng.
Mechanical Industry Standard of the People's Republic of China
Technical Conditions for Internal Combustion Engine Shell and Tube Oil Coolerg-Specificationg
JB/T$135-1999
Generation J:T
The standard specifies the basic requirements, main technical indicators and test rules that must be followed for shell and tube oil coolers for internal combustion engines, such as water and heat transfer performance.
This standard is used for internal combustion shell and tube oil coolers (hereinafter referred to as coolers) that are matched with automobiles, towing machinery, engineering machinery, small boats and engines.
2 Referenced standards
The clauses contained in the above standards are quoted in this standard as the underlying clauses of this standard. When this standard is reprinted, the versions shown are all valid. All standards will be sufficient. The parties using this standard should consider using the following standard for the latest version of the escapability, GB/T2828-1987 batch inspection counting sampling procedures and sample tables (for the inspection of subsequent batches) GB/T1821-1983 Methods for determination of cleanliness of small and medium power internal combustion engines 3 Definitions
This standard adopts the original text.
3.! Shell-and-shell cooler
A two-dimensional optical tube with many parallel tubes in it (see Figure 1?) 3. 2 The channel for oil in the cooler.
3.3 The channel for water in the cooler.
3.4 The channel inside the heat sink of the cooler.
3.5 The channel outside the heat sink of the cooler.
3.6 Downstream
The flow direction of cooling water and the sump in the cooler is the same. 3. 7 Countercurrent
The flow direction of cooling water and oil in the cooler is opposite. National Machinery Industry Corridor 1999-09-17 approved 2000-01-01 implementation
4 Technical requirements
Zedu water
F8/T8175—1999
Full heat plate
Circular baffle waiting tank
National 2 Ring disc baffle Ling cooling device
Cold water
Sand cooling water
Learn more about you
Buy heat plate
South 3 Two-way crescent baffle Plate cooler
4. Products should be manufactured according to product drawings and technical documents approved by the prescribed procedures. Water type
Pure water
4.2 The structural materials used in the cooling group should have an anti-corrosion coating in the working medium. During the specified service life of the cooler, the anti-corrosion performance should be complete.
4.3 The structure of the cooler must ensure that when the pipe is broken or blocked, it has the ability to be disassembled and the interchangeability of the core, and ensure that it is easy to clean the sediment and scale in the plug
4.4 Virtual performance test
.IR.T 812S--1999
The prepared cooler should be sealed under the pressure of 400kPa with 700kPu water. According to the user's requirements, the dynamic and water test standards of automotive diesel engines, diesel engines and special internal combustion engine coolers can be determined by cooperation between the two parties. 4.5 Vibration performance test The cooler filled with water is subjected to 4 times the square acceleration (). The vibration test is carried out according to the frequency and number of vibrations specified in Table 1. The test is carried out in sequence for 12×10 times. No leakage is allowed. The full flow amplitude A is determined according to the formula: Wherein: square acceleration, g.Blmis:
—frequency, Hzu
4.6 Duration performance test 4=4×10/2
Part time
The oil cavity of the cooler is filled with medium, and the medium temperature is 9 ± 1, the medium pressure should be changed in a circular manner, rising from 0.1 to 500% and holding, then falling from 5MmkPaF to 4, rising, holding, and falling each take 2s, that is, 6: time is 1 cycle, a total of 3×10 ohm cycles, this light is not allowed to have leakage, welding and parts damage, 4.7 Heat transfer performance test
Water is passed through the tube side, shell-like condensed oil (No. 11 or No. 14 diesel engine oil) water speed is 0.Sg. Oil speed is [.0In's, water inlet temperature is 5℃±1, oil temperature is 95℃±1℃, fluid flow direction is delivery flow, the main heat transfer performance indicators of the cooler should meet the requirements 4.7.1 Heat transfer coefficient K point is greater than or equal to 500W/(m*,℃), and is determined by formula (2): K.
1000 G. C_ ta
Use dry single-channel cooling water:
Use for process cooling water:
At: Cg)-(o-)
[al -fm
Oil heat dissipation plate,;
Oil-like heat transfer area, m
JB/T8125—1999
[f,-t --+
G=Yap:
Note: The calculation method of the oil side heat treatment F is proposed in Appendix A (non-gradient], A
logarithmic mean temperature, sink;
mass flow rate of sump, kh:
specific heat capacity of sump, k·(k·K):
-cooler oil inlet temperature, it;
cooler oil outlet temperature, ";
cooler water inlet temperature, T
-cooler water outlet temperature, T;
--.-body flow rate of engine oil, m/h;
product , - oil feel, kg'm
4.7.2 Volume utilization coefficient K should be greater than or equal to 115×10W/(m·T), and determined by formula (3)! K
Cooler energy volume, m
4.7.3 Mass barrier utilization coefficient * should be greater than or equal to 45W/(kg+) and determined by formula 14! K
Where: 9
Cooler mass, kg
4.7.4 Oil side difference, should be less than or equal to 65kPaa4.7.5 The heat transfer performance index of the cooler should be measured at the specified water speed and oil speed. 4.7.5.1 Water velocity is calculated by formula (5):
Where: K
Volume flow rate of water, :
Calculate the channel area,
The channel area on the water side is calculated according to Appendix B (Appendix of Standardization). 4.7.5.2 Oil velocity. According to formula (6): 3600S
Where: V
is the volume flow rate of engine oil, mh;
S is the channel area measured, m.
The channel area on the oil side is calculated according to Appendix B.
JB/T8125-1999
4.7.6 The oil side desmearing degree w, should be less than or equal to (45176F.) mg. 4.8 The cooler surface is not allowed to grow on the row, deformation, solder aggregation and electric welding spatter. 4.9 The cooler shall be equipped with air and water discharge devices in the inner cavity. 4.10 The cooler for special-purpose internal combustion engines shall be manufactured according to user requirements. 4.11 When manufacturing the cooler, the flow cross-section shall not be reduced due to pressure on the ends. The number of pipes that are allowed to be blocked due to defects in the pipe itself shall not exceed 1% of the total number of pipes. Defective pipes shall be blocked from both ends. 4.12 The cooler matched with the marine oil engine shall be manufactured in accordance with the regulations stipulated by the ship inspection department and under its technical supervision. 5 Test methods and acceptance rules
s.1 Test method
5.1.1 Dynamic performance test
The test shall be carried out on the dynamic test bench according to the conditions specified in 4.5. 5.1.2 Long-term performance test
On the long-term test bench, test according to the working record specified in 4.6. 5.1.3 Tightness performance test
On the sealing test bench, pass the compressed air with a pressure lower than 100% specified in 4.4 through the cooler in the water tank, keep it for 1 minute, and test the oil side and water side respectively. No air bubbles should appear. 1.4 Determination of oil cleanliness
Inject the cooler and seal the oil inlet and outlet of the test gasoline that occupies 60% of the oil chamber volume! 1. Place it on the vibration test bench. Vibrate at a rate of 5.81[z, 14min, and vibrate 2000 times continuously. Then test it according to the provisions of GB 3821. 5.1.5 Determination of heat transfer performance and heat dissipation resistance During the heat transfer performance test, on the heat transfer performance test bench, according to the working conditions specified in this standard, the heat balance error is controlled within the range of ± 5%. The heat transfer plate is measured, and then K is calculated according to formula (2): K is calculated according to formula (3), and K is output according to formula (4). During the heat transfer performance test, the oil side pressure difference is output at the same time. 5.1 Acceptance criteria 5.21 Products must be inspected by the quality inspection department of the manufacturer before they can leave the factory. 5.2.2 When the ordering unit randomly inspects the products, it shall follow the provisions of GB/T2828 and the relevant standards to agree on the acceptance rules and conduct acceptance. 6 Marking, packaging, transportation and storage 6.4.1 Each product shall be marked with: a) manufacturer's name or trademark; b) product model and name; c) factory date or factory abbreviation.
6.1.2 The location, size and method of marking shall comply with the provisions of the product sample approved by the prescribed procedures. The marking shall be intact during the entire use period of the product.
6.2 Packaging
6.2.1 The oil inlet and outlet and the water outlet shall be covered to prevent the cooler cavity from being contaminated. JB/8125—1999
62.2 Products that need to be transported over long distances as spare parts shall be packaged properly. 6.2.3 The packaging method shall ensure that the product is not damaged during transportation and storage. There is no manufacturing inside the box! The packing list signed by the packer shall indicate the product name, model, number and packing instructions. 6.2. 41
62.5 The packing box shall contain the product certificate and instructions for use signed by the quality inspector of the manufacturer. The certificate shall clearly indicate: 4) Manufacturer name or factory logo:
b) Product name and model:
c) Date of manufacture or factory number.
6.2.6 The packing box shall indicate
a) Manufacturer name and factory logo:
b) Product name and model:
Number and general description of the packing box:
d) "Caution", "Stand upright" and other signs: Overall dimensions:
f) Date of manufacture.
6.3 Transportation
A well-packed cooler shall be allowed to be transported by any normal method. 6.4 Storage The cooler should be stored in a ventilated and dry warehouse. Under proper storage, the manufacturer guarantees that the cooler will not rust within 12 months from the date of leaving the factory. The heat transfer area on the tube side is calculated by the heat transfer area formula (A): Where: Small - inner diameter of the heat transfer tube, m: JB/T8125-1999 Appendix A (Standard Appendix) t||Calculation method of heat transfer area
L—length of heat dissipation part of heat pipe, m:—number of heat pipes.
A2 Shell side heat transfer area
The shell side heat transfer area is composed of the bare pipe area F of the heat pipe and the area of the heat sink welded on the bare pipe (excluding the area of the baffle plate installed on the bare pipe). If there is no heat sink on the shell side of the cooler [as shown in Figure 2, the heat transfer area on the shell side is equal to the bare pipe area of the heat pipe! The bare pipe area of the heat pipe is calculated according to formula (A2): Fa=rd, Ln
Where: 4.--Outer diameter of heat pipe. m.
The area of heat radiating fin (see circle A) is calculated according to formula (A3): H =2[mR\-(L,RC,RC)-
Wu Zhong: R
Radiation fin radius, m;
-Arm length of heat radiating fin, m
-Chord length of heat collecting fin AB. m:
h-Height of heat collecting fin AB, m:
-Heat radiating fin work.Number of heat pipe holes;
-Number of heat radiating fins.
Shell heat transfer area positive, connect formula (4) to calculate hoop: F,= Fau+
3 Calculation example
JE/T8125-1999
Figure AI heat sink
6135G oil cooler [water on the sound side, oil on the charging side) calculation of heat transfer area: Parameters: heat pipe inner diameter d=6×10-m: heat pipe outer diameter d=? ×10-m: heat pipe heating part equal length 1-380m; heat sink number 120: heat sink half weight = 63×10-: heat plate AB arc height = 17×10~m; heat plate AB length L, = 94.8 ×10-blood: chord length of heat sink AB C, = 86 × 10 * m: number of heat sinks N-26; number of heat pipe holes on the heat sink n = 108, pipe measurement heat transfer area (also μ water side heat transfer area): F = FErdm
xt×10-3x0.380x120
=0.859(m)
light side heat transfer enthalpy! (also oil steel heat transfer area: PF-Fi+F
Fd, Ln
= yuan × 7 × 10 × 0.380 × 120
=1 3(m*)
F = 2R -(2,R -C,R - C,,)-
JB/T 8125—1999
-2[ × (63 × 10-1) (94.6 × 10-*×63 × 10-386 × 10-* × 63 × 10-3 86 × 10- 10-1 )1
ar × (7 x 10-1 × 081 × 26=0.327 (m)
F;=F,=1.003+0.327=1.33 (m*)
.TE/T8125-1999
Appendix B
(Appendix of standard)
Calculation of channel area
The heat transfer performance indicators listed in this standard refer to the measurements taken under the specified water velocity and oil condition. When calculating the flow rate, the channel area on the permanent side and the oil side of the cooler must be determined.
Calculation of the channel area S, on the tube side
The channel area S on the shell side is calculated according to formula (B1): S
B2Calculation of the channel area 3, on the shell side
The medium flows through the tube bundle outside the tube. The channel area it flows through is not a single number. This standard stipulates that the minimum channel area of the fluid cross-tube bundle is the channel area outside the cooler tube (see Figure A1). The channel area S on the shell side is calculated according to formula (2): S.-(cn,d,b .........
In the formula: C
-the length of the heat sink along the center line of each row of tube holes, m:
holes-the number of tube holes on the heat sink in the center and direction of each row of tube holes. B3 Calculation example
Calculation of the channel area of the oil cooling end of 6135G (water on the tube side and oil on the shell side). Calculation of the water channel area:
×(6×10-3)×120
=3.39 ×10-(m2)
Oil channel area According to formula (2), the appropriate area of each row of tubes is calculated and listed in Table B1. From Table B1, it can be seen that the second row of heat sinks has 9 tubes and the channel area on the bright side is the smallest.
Left 5S,-0.4682×10-【m2】
Order of rows
86.1 × [0-3
98.2 x 10-*
1D9.1×10-
116.9×30
122.1 × 10
125.1 ×10r
0.5865×10r1
0.4692×10rl
0.52 4XI×1(-
0.5307×10
0.6929 ×10
0.6397 ×10181[z rate, 14m vibration, 2000 times of continuous vibration, and then tested according to the provisions of GB/T 3821. 5.1.5 Determination of heat transfer performance and heat dissipation resistance During the heat transfer performance test, on the heat transfer performance test bench, according to the working conditions specified in this standard, the heat balance error is controlled within the range of ± 5%. The heat transfer plate is measured, and then K is calculated according to formula (2): K is calculated according to formula (3), and K is output according to formula (4). During the heat transfer performance test, the oil side pressure difference is output at the same time. 5.1 Acceptance criteria 5.21 Products must be inspected by the quality inspection department of the manufacturer before they can leave the factory. 5.2.2 When the ordering unit randomly inspects products, it shall follow the provisions of GB/T2828 and the relevant standards to agree on the acceptance rules and conduct acceptance. 6 Marking, packaging, transportation and storage 6.4.1 Each product shall be marked with: a) manufacturer's name or trademark; b) product model and name; c) factory date or factory abbreviation.
6.1.2 The location, size and method of marking shall comply with the provisions of the product sample approved by the prescribed procedures. The marking shall be intact during the entire use period of the product.
6.2 Packaging
6.2.1 The oil inlet and outlet and the water outlet shall be covered to prevent the cooler cavity from being contaminated. JB/8125—1999
62.2 Products that need to be transported over long distances as spare parts shall not be packaged properly. 6.2.3 The packaging method shall ensure that the product is not damaged during transportation and storage. There is no manufacturing inside the box! The packing list signed by the packer shall indicate the product name, model, number and packing instructions. 6.2. 41
62.5 The packing box shall contain the product certificate and instructions for use signed by the quality inspector of the manufacturer. The certificate shall clearly indicate: 4) Manufacturer name or factory logo:
b) Product name and model:
c) Date of manufacture or factory number.
6.2.6 The packing box shall indicate
a) Manufacturer name and factory logo:
b) Product name and model:
Number and general description of the packing box:
d) "Caution", "Stand upright" and other signs: Overall dimensions:
f) Date of manufacture.
6.3 Transportation
A well-packed cooler shall be allowed to be transported by any normal method. 6.4 Storage The cooler should be stored in a ventilated and dry warehouse. Under proper storage, the manufacturer guarantees that the cooler will not rust within 12 months from the date of leaving the factory. The heat transfer area on the tube side is calculated by the heat transfer area formula (A): Where: Small - inner diameter of the heat transfer tube, m: JB/T8125-1999 Appendix A (Standard Appendix) t||Calculation method of heat transfer area
L—length of heat dissipation part of heat pipe, m:—number of heat pipes.
A2 Shell side heat transfer area
The shell side heat transfer area is composed of the bare pipe area F of the heat pipe and the heat sink area F welded on the bare pipe (excluding the baffle area assembled on the bare pipe). If there is no heat sink on the shell side of the cooler [as shown in Figure 2, the heat transfer area on the shell side is equal to the bare pipe area of the heat pipe! The bare pipe area of the heat pipe is calculated according to formula (A2): Fa=rd, Ln
Where: 4.--Outer diameter of heat pipe. m.
The area of heat radiating fin (see A) is calculated according to formula (A3): H =2[mR\-(L,RC,RC)-
Wu Zhong: R
Radiation fin radius, m;
-Arm length of heat radiating fin, m
-Chord length of heat collecting fin AB. m:
h-Height of heat collecting fin AB, m:
-Heat radiating fin work.Number of heat pipe holes;
-Number of heat radiating fins.
Shell heat transfer area positive, connect formula (4) to calculate hoop: F,= Fau+
3 Calculation example
JE/T8125-1999
Figure AI heat sink
6135G oil cooler [water on the sound side, oil on the charging side) calculation of heat transfer area: Parameters: heat pipe inner diameter d=6×10-m: heat pipe outer diameter d=? ×10-m: heat pipe heating part equal length 1-380m; heat sink number 120: heat sink half weight = 63×10-: heat plate AB arc height = 17×10~m; heat plate AB length L, = 94.8 ×10-blood: chord length of heat sink AB C, = 86 × 10 * m: number of heat sinks N-26; number of heat pipe holes on the heat sink n = 108, pipe measurement heat transfer area (also μ water side heat transfer area): F = FErdm
xt×10-3x0.380x120
=0.859(m)
light side heat transfer enthalpy! (also oil steel heat transfer area: PF-Fi+F
Fd, Ln
= yuan × 7 × 10 × 0.380 × 120
=1 3(m*)
F = 2R -(2,R -C,R - C,,)-
JB/T 8125—1999
-2[ × (63 × 10-1) (94.6 × 10-*×63 × 10-386 × 10-* × 63 × 10-3 86 × 10- 10-1 )1
ar × (7 x 10-1 × 081 × 26=0.327 (m)
F;=F,=1.003+0.327=1.33 (m*)
.TE/T8125-1999
Appendix B
(Appendix of Accuracy)
Calculation of channel area
The heat transfer performance indicators listed in this standard refer to those measured under the specified water velocity and oil condition. When calculating the flow rate, the channel area on the permanent side and the oil side of the cooler must be determined.
Calculation of tube channel area S,
The channel area S on the shell side is calculated according to formula (B1): S
B2Calculation of shell side channel area 3,
The medium flows through the tube bundle outside the tube. The channel area it flows through is not a single number. This standard stipulates that the minimum channel area of the fluid cross-tube bundle is the channel area outside the cooler tube (see Figure A1). The channel area S on the shell side is calculated according to formula (2): S.-(cn,d,b .........
In the formula: C
-the length of the heat sink along the center line of each row of tube holes, m:
holes-the number of tube holes on the heat sink in the center and direction of each row of tube holes. B3 Calculation example
Calculation of the channel area of the 6135G oil cooling end (water on the tube side, oil on the shell side). Calculation of the water channel area:
×(6×10-3)×120
=3.39 ×10-(m2)
Oil channel area According to formula (2), the appropriate area of each row of tubes is calculated and listed in Table B1. From Table B1, it can be seen that the second row of heat sinks has 9 tubes, and the channel area on the bright side is the smallest.
Left 5S,-0.4682×10-【m2】
Order of rows
86.1 × [0-3
98.2 x 10-*
1D9.1×10-
116.9×30
122.1 × 10
125.1 ×10r
0.5865×10r1
0.4692×10rl
0.52 4XI×1(-
0.5307×10
0.6929 ×10
0.6397 ×10181[z rate, 14m vibration, 2000 times of continuous vibration, and then tested according to the provisions of GB/T 3821. 5.1.5 Determination of heat transfer performance and heat dissipation resistance During the heat transfer performance test, on the heat transfer performance test bench, according to the working conditions specified in this standard, the heat balance error is controlled within the range of ± 5%. The heat transfer plate is measured, and then K is calculated according to formula (2): K is calculated according to formula (3), and K is output according to formula (4). During the heat transfer performance test, the oil side pressure difference is output at the same time. 5.1 Acceptance criteria 5.21 Products must be inspected by the quality inspection department of the manufacturer before they can leave the factory. 5.2.2 When the ordering unit randomly inspects the products, it shall follow the provisions of GB/T2828 and the relevant standards to agree on the acceptance rules and conduct acceptance. 6 Marking, packaging, transportation and storage 6.4.1 Each product shall be marked with: a) manufacturer's name or trademark; b) product model and name; c) factory date or factory abbreviation.
6.1.2 The location, size and method of marking shall comply with the provisions of the product sample approved by the prescribed procedures. The marking shall be intact during the entire use period of the product.
6.2 Packaging
6.2.1 The oil inlet and outlet and the water outlet shall be covered to prevent the cooler cavity from being contaminated. JB/8125—1999
62.2 Products that need to be transported over long distances as spare parts shall be packaged properly. 6.2.3 The packaging method shall ensure that the product is not damaged during transportation and storage. There is no manufacturing inside the box! The packing list signed by the packer shall indicate the product name, model, number and packing instructions. 6.2. 41
62.5 The packing box shall contain the product certificate and instructions for use signed by the quality inspector of the manufacturer. The certificate shall clearly indicate: 4) Manufacturer name or factory logo:
b) Product name and model:
c) Date of manufacture or factory number.
6.2.6 The packing box shall indicate
a) Manufacturer name and factory logo:
b) Product name and model:
Number and general description of the packing box:
d) "Caution", "Stand upright" and other signs: Overall dimensions:
f) Date of manufacture.
6.3 Transportation
A well-packed cooler shall be allowed to be transported by any normal method. 6.4 Storage The cooler should be stored in a ventilated and dry warehouse. Under proper storage, the manufacturer guarantees that the cooler will not rust within 12 months from the date of leaving the factory. The heat transfer area on the tube side is calculated by the heat transfer area formula (A): Where: Small - inner diameter of the heat transfer tube, m: JB/T8125-1999 Appendix A (Standard Appendix) t||Calculation method of heat transfer area
L—length of heat dissipation part of heat pipe, m:—number of heat pipes.
A2 Shell side heat transfer area
The shell side heat transfer area is composed of the bare pipe area F of the heat pipe and the area of the heat sink welded on the bare pipe (excluding the area of the baffle plate installed on the bare pipe). If there is no heat sink on the shell side of the cooler [as shown in Figure 2, the heat transfer area on the shell side is equal to the bare pipe area of the heat pipe! The bare pipe area of the heat pipe is calculated according to formula (A2): Fa=rd, Ln
Where: 4.--Outer diameter of heat pipe. m.
The area of heat radiating fin (see A) is calculated according to formula (A3): H =2[mR\-(L,RC,RC)-
Wu Zhong: R
Radiation fin radius, m;
-Arm length of heat radiating fin, m
-Chord length of heat collecting fin AB. m:bzxZ.net
h-Height of heat collecting fin AB, m:
-Heat radiating fin work.Number of heat pipe holes;
-Number of heat radiating fins.
Shell heat transfer area positive, connect formula (4) to calculate hoop: F,= Fau+
3 Calculation example
JE/T8125-1999
Figure AI heat sink
6135G oil cooler [water on the sound side, oil on the charging side) calculation of heat transfer area: Parameters: heat pipe inner diameter d=6×10-m: heat pipe outer diameter d=? ×10-m: heat pipe heating part equal length 1-380m; heat sink number 120: heat sink half weight = 63×10-: heat plate AB arc height = 17×10~m; heat plate AB length L, = 94.8 ×10-blood: chord length of heat sink AB C, = 86 × 10 * m: number of heat sinks N-26; number of heat pipe holes on the heat sink n = 108, pipe measurement heat transfer area (also μ water side heat transfer area): F = FErdm
xt×10-3x0.380x120
=0.859(m)
light side heat transfer enthalpy! (also oil steel heat transfer area: PF-Fi+F
Fd, Ln
= yuan × 7 × 10 × 0.380 × 120
=1 3(m*)
F = 2R -(2,R -C,R - C,,)-
JB/T 8125—1999
-2[ × (63 × 10-1) (94.6 × 10-*×63 × 10-386 × 10-* × 63 × 10-3 86 × 10- 10-1 )1
ar × (7 x 10-1 × 081 × 26=0.327 (m)
F;=F,=1.003+0.327=1.33 (m*)
.TE/T8125-1999
Appendix B
(Appendix of standard)
Calculation of channel area
The heat transfer performance indicators listed in this standard refer to the measurements taken under the specified water velocity and oil condition. When calculating the flow rate, the channel area on the permanent side and the oil side of the cooler must be determined.
Calculation of the channel area S, on the tube side
The channel area S on the shell side is calculated according to formula (B1): S
B2Calculation of the channel area 3, on the shell side
The medium flows through the tube bundle outside the tube. The channel area it flows through is not a single number. This standard stipulates that the minimum channel area of the fluid cross-tube bundle is the channel area outside the cooler tube (see Figure A1). The channel area S on the shell side is calculated according to formula (2): S.-(cn,d,b .........
In the formula: C
-the length of the heat sink along the center line of each row of tube holes, m:
holes-the number of tube holes on the heat sink in the center and direction of each row of tube holes. B3 Calculation example
Calculation of the channel area of the oil cooling end of 6135G (water on the tube side and oil on the shell side). Calculation of the water channel area:
×(6×10-3)×120
=3.39 ×10-(m2)
Oil channel area According to formula (2), the appropriate area of each row of tubes is calculated and listed in Table B1. From Table B1, it can be seen that the second row of heat sinks has 9 tubes and the channel area on the bright side is the smallest.
Left 5S,-0.4682×10-【m2】
Order of rows
86.1 × [0-3
98.2 x 10-*
1D9.1×10-
116.9×30
122.1 × 10
125.1 ×10r
0.5865×10r1
0.4692×10rl
0.52 4XI×1(-
0.5307×10
0.6929 ×10
0.6397 ×1012 Packaging
6.2.1 The oil inlet and outlet and the water inlet should be covered to prevent the cooler cavity from being contaminated. JB/8125—1999
62.2 Products that need to be transported over long distances as spare parts should be packaged properly. 6.2.3 The packaging method should ensure that the product is not damaged during transportation and storage. There should be a packing list signed by the manufacturer and the packing list should indicate the product name, model, number and packing number. 6.2. 41
62.5 The packaging box should have a product certificate and instructions signed by the manufacturer's quality inspector. The certificate should clearly indicate: 4) Manufacturer's name or factory logo:
b) Product name and model:
c) Date of manufacture or factory number.
6.2.6 The packaging box should be marked with
a) Factory name and factory extension:
b) Product name and model:
Number and general description of the packaging box:
d) "Be careful" and "Stand straight" signs: Overall dimensions:
f) "Date of shipment".
6.3 Transportation
A well-packaged cooler can be transported by any normal method. 6.4 Storage The cooler should be stored in a ventilated and dry warehouse. Under proper storage, the manufacturer guarantees that the cooler will not rust within 12 months from the date of leaving the factory. The heat transfer area on the tube side is calculated by the heat transfer area formula (A): Where: Small - inner diameter of the heat transfer tube, m: JB/T8125-1999 Appendix A (Standard Appendix) t||Calculation method of heat transfer area
L—length of heat dissipation part of heat pipe, m:—number of heat pipes.
A2 Shell side heat transfer area
The shell side heat transfer area is composed of the bare pipe area F of the heat pipe and the area of the heat sink welded on the bare pipe (excluding the area of the baffle plate installed on the bare pipe). If there is no heat sink on the shell side of the cooler [as shown in Figure 2, the heat transfer area on the shell side is equal to the bare pipe area of the heat pipe! The bare pipe area of the heat pipe is calculated according to formula (A2): Fa=rd, Ln
Where: 4.--Outer diameter of heat pipe. m.
The area of heat radiating fin (see A) is calculated according to formula (A3): H =2[mR\-(L,RC,RC)-
Wu Zhong: R
Radiation fin radius, m;
-Arm length of heat radiating fin, m
-Chord length of heat collecting fin AB. m:
h-Height of heat collecting fin AB, m:
-Heat radiating fin work.Number of heat pipe holes;
-Number of heat radiating fins.
Shell heat transfer area positive, connect formula (4) to calculate hoop: F,= Fau+
3 Calculation example
JE/T8125-1999
Figure AI heat sink
6135G oil cooler [water on the sound side, oil on the charging side) calculation of heat transfer area: Parameters: heat pipe inner diameter d=6×10-m: heat pipe outer diameter d=? ×10-m: heat pipe heating part equal length 1-380m; heat sink number 120: heat sink half weight = 63×10-: heat plate AB arc height = 17×10~m; heat plate AB length L, = 94.8 ×10-blood: chord length of heat sink AB C, = 86 × 10 * m: number of heat sinks N-26; number of heat pipe holes on the heat sink n = 108, pipe measurement heat transfer area (also μ water side heat transfer area): F = FErdm
xt×10-3x0.380x120
=0.859(m)
light side heat transfer enthalpy! (also oil steel heat transfer area: PF-Fi+F
Fd, Ln
= yuan × 7 × 10 × 0.380 × 120
=1 3(m*)
F = 2R -(2,R -C,R - C,,)-
JB/T 8125—1999
-2[ × (63 × 10-1) (94.6 × 10-*×63 × 10-386 × 10-* × 63 × 10-3 86 × 10- × 17 10-1 )1
ar × (7 x 10-1 × 081 × 26=0.327 (m)
F;=F,=1.003+0.327=1.33 (m*)
.TE/T8125-1999
Appendix B
(Appendix of standard)
Calculation of channel area
The heat transfer performance indicators listed in this standard refer to the measurements taken under the specified water velocity and oil condition. When calculating the flow rate, the channel area on the permanent side and the oil side of the cooler must be determined.
Calculation of the channel area S, on the tube side
The channel area S on the shell side is calculated according to formula (B1): S
B2Calculation of the channel area 3, on the shell side
The medium flows through the tube bundle outside the tube. The channel area it flows through is not a single number. This standard stipulates that the minimum channel area of the fluid cross-tube bundle is the channel area outside the cooler tube (see Figure A1). The channel area S on the shell side is calculated according to formula (2): S.-(cn,d,b .........
In the formula: C
-the length of the heat sink along the center line of each row of tube holes, m:
holes-the number of tube holes on the heat sink in the center and direction of each row of tube holes. B3 Calculation example
Calculation of the channel area of the oil cooling end of 6135G (water on the tube side and oil on the shell side). Calculation of the water channel area:
×(6×10-3)×120
=3.39 ×10-(m2)
Oil channel area According to formula (2), the appropriate area of each row of tubes is calculated and listed in Table B1. From Table B1, it can be seen that the second row of heat sinks has 9 tubes and the channel area on the bright side is the smallest.
Left 5S,-0.4682×10-【m2】
Order of rows
86.1 × [0-3
98.2 x 10-*
1D9.1×10-
116.9×30
122.1 × 10
125.1 ×10r
0.5865×10r1
0.4692×10rl
0.52 4XI×1(-
0.5307×10
0.6929 ×10
0.6397 ×1012 Packaging
6.2.1 The oil inlet and outlet and the water inlet should be covered to prevent the cooler cavity from being contaminated. JB/8125—1999
62.2 Products that need to be transported over long distances as spare parts should be packed separately. 6.2.3 The packaging method should ensure that the product is not damaged during transportation and storage. There should be a packing list signed by the manufacturer and the packing list should indicate the product name, model, number and packing number. 6.2. 41
62.5 The packaging box should have a product certificate and instructions signed by the manufacturer's quality inspector. The certificate should clearly indicate: 4) Manufacturer's name or factory logo:
b) Product name and model:
c) Date of manufacture or factory number.
6.2.6 The packaging box should be marked with
a) Factory name and factory extension:
b) Product name and model:
Number and general description of the packaging box:
d) "Be careful" and "Stand straight" signs: Overall dimensions:
f) "Date of shipment".
6.3 Transportation
A well-packaged cooler can be transported by any normal method. 6.4 Storage The cooler should be stored in a ventilated and dry warehouse. Under proper storage, the manufacturer guarantees that the cooler will not rust within 12 months from the date of leaving the factory. The heat transfer area on the tube side is calculated by the heat transfer area formula (A): Where: Small - inner diameter of the heat transfer tube, m: JB/T8125-1999 Appendix A (Standard Appendix) t||Calculation method of heat transfer area
L—length of heat dissipation part of heat pipe, m:—number of heat pipes.
A2 Shell side heat transfer area
The shell side heat transfer area is composed of the bare pipe area F of the heat pipe and the heat sink area F welded on the bare pipe (excluding the baffle area assembled on the bare pipe). If there is no heat sink on the shell side of the cooler [as shown in Figure 2, the heat transfer area on the shell side is equal to the bare pipe area of the heat pipe! The bare pipe area of the heat pipe is calculated according to formula (A2): Fa=rd, Ln
Where: 4.--Outer diameter of heat pipe. m.
The area of heat radiating fin (see A) is calculated according to formula (A3): H =2[mR\-(L,RC,RC)-
Wu Zhong: R
Radiation fin radius, m;
-Arm length of heat radiating fin, m
-Chord length of heat collecting fin AB. m:
h-Height of heat collecting fin AB, m:
-Heat radiating fin work.Number of heat pipe holes;
-Number of heat radiating fins.
Shell heat transfer area positive, connect formula (4) to calculate hoop: F,= Fau+
3 Calculation example
JE/T8125-1999
Figure AI heat sink
6135G oil cooler [water on the sound side, oil on the charging side) calculation of heat transfer area: Parameters: heat pipe inner diameter d=6×10-m: heat pipe outer diameter d=? ×10-m: heat pipe heating part equal length 1-380m; heat sink number 120: heat sink half weight = 63×10-: heat plate AB arc height = 17×10~m; heat plate AB length L, = 94.8 ×10-blood: chord length of heat sink AB C, = 86 × 10 * m: number of heat sinks N-26; number of heat pipe holes on the heat sink n = 108, pipe measurement heat transfer area (also μ water side heat transfer area): F = FErdm
xt×10-3x0.380x120
=0.859(m)
light side heat transfer enthalpy! (also oil steel heat transfer area: PF-Fi+F
Fd, Ln
= yuan × 7 × 10 × 0.380 × 120
=1 3(m*)
F = 2R -(2,R -C,R - C,,)-
JB/T 8125—1999
-2[ × (63 × 10-1) (94.6 × 10-*×63 × 10-386 × 10-* × 63 × 10-3 86 × 10- 10-1 )1
ar × (7 x 10-1 × 081 × 26=0.327 (m)
F;=F,=1.003+0.327=1.33 (m*)
.TE/T8125-1999
Appendix B
(Appendix of Accuracy)
Calculation of channel area
The heat transfer performance indicators listed in this standard refer to those measured under the specified water velocity and oil condition. When calculating the flow rate, the channel area on the permanent side and the oil side of the cooler must be determined.
Calculation of tube channel area S,
The channel area S on the shell side is calculated according to formula (B1): S
B2Calculation of shell side channel area 3,
The medium flows through the tube bundle outside the tube. The channel area it flows through is not a single number. This standard stipulates that the minimum channel area of the fluid cross-tube bundle is the channel area outside the cooler tube (see Figure A1). The channel area S on the shell side is calculated according to formula (2): S.-(cn,d,b .........
In the formula: C
-the length of the heat sink along the center line of each row of tube holes, m:
holes-the number of tube holes on the heat sink in the center and direction of each row of tube holes. B3 Calculation example
Calculation of the channel area of the 6135G oil cooling end (water on the tube side, oil on the shell side). Calculation of the water channel area:
×(6×10-3)×120
=3.39 ×10-(m2)
Oil channel area According to formula (2), the appropriate area of each row of tubes is calculated and listed in Table B1. From Table B1, it can be seen that the second row of heat sinks has 9 tubes, and the channel area on the bright side is the smallest.
Left 5S,-0.4682×10-【m2】
Order of rows
86.1 × [0-3
98.2 x 10-*
1D9.1×10-
116.9×30
122.1 × 10
125.1 ×10r
0.5865×10r1
0.4692×10rl
0.52 4XI×1(-
0.5307×10
0.6929 ×10
0.6397 ×101RC)-
Wu Zhong: R
Radius of heat sink, m;
-Arm length of heat sink, m
-Chord length of heat sink AB, m:
h-Height of heat sink AB, m:
-Heat sink work.Number of heat pipe holes;
-Number of heat sinks.
Shell heat transfer area positive, connect formula (4) calculation: F, = Fau+
3 Calculation example
JE/T8125-1999
Figure AI heat sink
6135G oil cooler [water on the sound side, oil on the filling side) Calculation of heat transfer area: Number: Heat pipe inner diameter d=6×10-m: Heat pipe outer diameter d=? ×10-m: the length of the heating part of the heat pipe is 1-380m; the number of heat sinks is 120: the half weight of the heat sink = 63×10-: the arc height of the heat sink AB = 17×10~m; the length of heat sink AB L, = 94.8×10-blood: the chord length of the heat sink AB C, = 86×10*m: the number of heat sinks N-26; the number of heat pipe holes on the heat sink n=108, the measured heat transfer area of the tube (also the heat transfer area on the water side): F=FErdm
xt×10-3x0.380x120
=0.859(m)
the heat transfer enthalpy on the light side! (That is, the oil-to-steel heat transfer area: PF-Fi+F
Fd,Ln
=yuan×7×10×0.380×120
=1 3(m*)
F = 2R -(2,R -C,R - C,,)-
JB/T 8125—1999
-2[ × (63 × 10-1) (94.6 × 10-*×63 × 10-386 × 10-* × 63 × 10-3 86 × 10- × 17 × 10-1 )1
ar × (7 x 10-1 × 081 × 26=0.327 (m)
F;=F,=1.003+0.327=1.33 (m*)
.TE/T8125-1999
Appendix B
(Appendix of Accuracy)
Calculation of channel area
The heat transfer performance indicators listed in this standard refer to those measured under the specified water velocity and oil condition. When calculating the flow rate, the channel area on the permanent side and the oil side of the cooler must be determined.
Calculation of tube channel area S,
The channel area S on the shell side is calculated according to formula (B1): S
B2Calculation of shell side channel area 3,
The medium flows through the tube bundle outside the tube. The channel area it flows through is not a single number. This standard stipulates that the minimum channel area of the fluid cross-tube bundle is the channel area outside the cooler tube (see Figure A1). The channel area S on the shell side is calculated according to formula (2): S.-(cn,d,b .........
In the formula: C
-the length of the heat sink along the center line of each row of tube holes, m:
holes-the number of tube holes on the heat sink in the center and direction of each row of tube holes. B3 Calculation example
Calculation of the channel area of the 6135G oil cooling end (water on the tube side, oil on the shell side). Calculation of the water channel area:
×(6×10-3)×120
=3.39 ×10-(m2)
Oil channel area According to formula (2), the appropriate area of each row of tubes is calculated and listed in Table B1. From Table B1, it can be seen that the second row of heat sinks has 9 tubes, and the channel area on the bright side is the smallest.
Left 5S,-0.4682×10-【m2】
Order of rows
86.1 × [0-3
98.2 x 10-*
1D9.1×10-
116.9×30
122.1 × 10
125.1 ×10r
0.5865×10r1
0.4692×10rl
0.52 4XI×1(-
0.5307×10
0.6929 ×10
0.6397 ×101RC)-
Wu Zhong: R
Radius of heat sink, m;
-Arm length of heat sink, m
-Chord length of heat sink AB, m:
h-Height of heat sink AB, m:
-Heat sink work.Number of heat pipe holes;
-Number of heat sinks.
Shell heat transfer area positive, connect formula (4) calculation: F, = Fau+
3Calculation example
JE/T8125-1999
Figure AI heat sink
6135G oil cooler [water on the sound side, oil on the filling side) Calculation of heat transfer area: Number: Heat pipe inner diameter d=6×10-m: Heat pipe outer diameter d=? ×10-m: the length of the heating part of the heat pipe is 1-380m; the number of heat sinks is 120: the half weight of the heat sink = 63×10-: the arc height of the heat sink AB = 17×10~m; the length of heat sink AB L, = 94.8×10-blood: the chord length of the heat sink AB C, = 86×10*m: the number of heat sinks N-26; the number of heat pipe holes on the heat sink n=108, the measured heat transfer area of the tube (also the heat transfer area on the water side): F=FErdm
xt×10-3x0.380x120
=0.859(m)
the heat transfer enthalpy on the light side! (That is, the oil-to-steel heat transfer area: PF-Fi+F
Fd,Ln
=yuan×7×10×0.380×120
=1 3(m*)
F = 2R -(2,R -C,R - C,,)-
JB/T 8125—1999
-2[ × (63 × 10-1) (94.6 × 10-*×63 × 10-386 × 10-* × 63 × 10-3 86 × 10- × 17 × 10-1 )1
ar × (7 x 10-1 × 081 × 26=0.327 (m)
F;=F,=1.003+0.327=1.33 (m*)
.TE/T8125-1999
Appendix B
(Appendix of standard)
Calculation of channel area
The heat transfer performance indicators listed in this standard refer to the measurements taken under the specified water velocity and oil condition. When calculating the flow rate, the channel area on the permanent side and the oil side of the cooler must be determined.
Calculation of the channel area S, on the tube side
The channel area S on the shell side is calculated according to formula (B1): S
B2Calculation of the channel area 3, on the shell side
The medium flows through the tube bundle outside the tube. The channel area it flows through is not a single number. This standard stipulates that the minimum channel area of the fluid cross-tube bundle is the channel area outside the cooler tube (see Figure A1). The channel area S on the shell side is calculated according to formula (2): S.-(cn,d,b .........
In the formula: C
-the length of the heat sink along the center line of each row of tube holes, m:
holes-the number of tube holes on the heat sink in the center and direction of each row of tube holes. B3 Calculation example
Calculation of the channel area of the oil cooling end of 6135G (water on the tube side and oil on the shell side). Calculation of the water channel area:
×(6×10-3)×120
=3.39 ×10-(m2)
Oil channel area According to formula (2), the appropriate area of each row of tubes is calculated and listed in Table B1. From Table B1, it can be seen that the second row of heat sinks has 9 tubes and the channel area on the bright side is the smallest.
Left 5S,-0.4682×10-【m2】
Order of rows
86.1 × [0-3
98.2 x 10-*
1D9.1×10-
116.9×30
122.1 × 10
125.1 ×10r
0.5865×10r1
0.4692×10rl
0.52 4XI×1(-
0.5307×10
0.6929 ×10
0.6397 ×101
Tip: This standard content only shows part of the intercepted content of the complete standard. If you need the complete standard, please go to the top to download the complete standard document for free.